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x2-39/9=0
We add all the numbers together, and all the variables
x^2-39/9=0
We multiply all the terms by the denominator
x^2*9-39=0
Wy multiply elements
9x^2-39=0
a = 9; b = 0; c = -39;
Δ = b2-4ac
Δ = 02-4·9·(-39)
Δ = 1404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1404}=\sqrt{36*39}=\sqrt{36}*\sqrt{39}=6\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{39}}{2*9}=\frac{0-6\sqrt{39}}{18} =-\frac{6\sqrt{39}}{18} =-\frac{\sqrt{39}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{39}}{2*9}=\frac{0+6\sqrt{39}}{18} =\frac{6\sqrt{39}}{18} =\frac{\sqrt{39}}{3} $
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