(2x+1)+(x+17)+(4x-15)=106

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Solution for (2x+1)+(x+17)+(4x-15)=106 equation: 



(2x+1)+(x+17)+(4x-15)=106

We move all terms to the left:

(2x+1)+(x+17)+(4x-15)-(106)=0

We get rid of parentheses

2x+x+4x+1+17-15-106=0

We add all the numbers together, and all the variables

7x-103=0

We move all terms containing x to the left, all other terms to the right

7x=103

x=103/7

x=14+5/7

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