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7(x+2)-3=3x+4(2+x)
We move all terms to the left:
7(x+2)-3-(3x+4(2+x))=0
We add all the numbers together, and all the variables
7(x+2)-(3x+4(x+2))-3=0
We multiply parentheses
7x-(3x+4(x+2))+14-3=0
We calculate terms in parentheses: -(3x+4(x+2)), so:We add all the numbers together, and all the variables
3x+4(x+2)
We multiply parentheses
3x+4x+8
We add all the numbers together, and all the variables
7x+8
Back to the equation:
-(7x+8)
7x-(7x+8)+11=0
We get rid of parentheses
7x-7x-8+11=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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