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3x+5x+1=2(x+4)
We move all terms to the left:
3x+5x+1-(2(x+4))=0
We add all the numbers together, and all the variables
8x-(2(x+4))+1=0
We calculate terms in parentheses: -(2(x+4)), so:We get rid of parentheses
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
8x-2x-8+1=0
We add all the numbers together, and all the variables
6x-7=0
We move all terms containing x to the left, all other terms to the right
6x=7
x=7/6
x=1+1/6
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