7(x+2)-13=3(x+12)-2

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Solution for 7(x+2)-13=3(x+12)-2 equation: 



7(x+2)-13=3(x+12)-2

We move all terms to the left:

7(x+2)-13-(3(x+12)-2)=0

We multiply parentheses

7x-(3(x+12)-2)+14-13=0



We calculate terms in parentheses: -(3(x+12)-2), so:

3(x+12)-2

We multiply parentheses

3x+36-2

We add all the numbers together, and all the variables

3x+34

Back to the equation:

-(3x+34)



We add all the numbers together, and all the variables

7x-(3x+34)+1=0

We get rid of parentheses

7x-3x-34+1=0

We add all the numbers together, and all the variables

4x-33=0

We move all terms containing x to the left, all other terms to the right

4x=33

x=33/4

x=8+1/4

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