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35x^2+24x+4=0
a = 35; b = 24; c = +4;
Δ = b2-4ac
Δ = 242-4·35·4
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4}{2*35}=\frac{-28}{70} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4}{2*35}=\frac{-20}{70} =-2/7 $
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