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4(2x-3)=5+x
We move all terms to the left:
4(2x-3)-(5+x)=0
We add all the numbers together, and all the variables
4(2x-3)-(x+5)=0
We multiply parentheses
8x-(x+5)-12=0
We get rid of parentheses
8x-x-5-12=0
We add all the numbers together, and all the variables
7x-17=0
We move all terms containing x to the left, all other terms to the right
7x=17
x=17/7
x=2+3/7
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