7(x+1)+3(3-x)=5(x-1)-3(2x+1)

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Solution for 7(x+1)+3(3-x)=5(x-1)-3(2x+1) equation: 



7(x+1)+3(3-x)=5(x-1)-3(2x+1)

We move all terms to the left:

7(x+1)+3(3-x)-(5(x-1)-3(2x+1))=0

We add all the numbers together, and all the variables

7(x+1)+3(-1x+3)-(5(x-1)-3(2x+1))=0

We multiply parentheses

7x-3x-(5(x-1)-3(2x+1))+7+9=0



We calculate terms in parentheses: -(5(x-1)-3(2x+1)), so:

5(x-1)-3(2x+1)

We multiply parentheses

5x-6x-5-3

We add all the numbers together, and all the variables

-1x-8

Back to the equation:

-(-1x-8)



We add all the numbers together, and all the variables

4x-(-1x-8)+16=0

We get rid of parentheses

4x+1x+8+16=0

We add all the numbers together, and all the variables

5x+24=0

We move all terms containing x to the left, all other terms to the right

5x=-24

x=-24/5

x=-4+4/5

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