2(4x+3)+3(2x-1)=32

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Solution for 2(4x+3)+3(2x-1)=32 equation: 



2(4x+3)+3(2x-1)=32

We move all terms to the left:

2(4x+3)+3(2x-1)-(32)=0

We multiply parentheses

8x+6x+6-3-32=0

We add all the numbers together, and all the variables

14x-29=0

We move all terms containing x to the left, all other terms to the right

14x=29

x=29/14

x=2+1/14

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