7(j-10)=7(2j+7)

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Solution for 7(j-10)=7(2j+7) equation: 



7(j-10)=7(2j+7)

We move all terms to the left:

7(j-10)-(7(2j+7))=0

We multiply parentheses

7j-(7(2j+7))-70=0



We calculate terms in parentheses: -(7(2j+7)), so:

7(2j+7)

We multiply parentheses

14j+49

Back to the equation:

-(14j+49)



We get rid of parentheses

7j-14j-49-70=0

We add all the numbers together, and all the variables

-7j-119=0

We move all terms containing j to the left, all other terms to the right

-7j=119

j=119/-7

j=-17

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