4(a+3)-3(a+2)=2(a-2)

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Solution for 4(a+3)-3(a+2)=2(a-2) equation: 



4(a+3)-3(a+2)=2(a-2)

We move all terms to the left:

4(a+3)-3(a+2)-(2(a-2))=0

We multiply parentheses

4a-3a-(2(a-2))+12-6=0



We calculate terms in parentheses: -(2(a-2)), so:

2(a-2)

We multiply parentheses

2a-4

Back to the equation:

-(2a-4)



We add all the numbers together, and all the variables

a-(2a-4)+6=0

We get rid of parentheses

a-2a+4+6=0

We add all the numbers together, and all the variables

-1a+10=0

We move all terms containing a to the left, all other terms to the right

-a=-10

a=-10/-1

a=+10

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