3(4c-15)=3(5c+7)

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Solution for 3(4c-15)=3(5c+7) equation: 



3(4c-15)=3(5c+7)

We move all terms to the left:

3(4c-15)-(3(5c+7))=0

We multiply parentheses

12c-(3(5c+7))-45=0



We calculate terms in parentheses: -(3(5c+7)), so:

3(5c+7)

We multiply parentheses

15c+21

Back to the equation:

-(15c+21)



We get rid of parentheses

12c-15c-21-45=0

We add all the numbers together, and all the variables

-3c-66=0

We move all terms containing c to the left, all other terms to the right

-3c=66

c=66/-3

c=-22

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