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7(f-1)-3=2(2f+1)+3
We move all terms to the left:
7(f-1)-3-(2(2f+1)+3)=0
We multiply parentheses
7f-(2(2f+1)+3)-7-3=0
We calculate terms in parentheses: -(2(2f+1)+3), so:We add all the numbers together, and all the variables
2(2f+1)+3
We multiply parentheses
4f+2+3
We add all the numbers together, and all the variables
4f+5
Back to the equation:
-(4f+5)
7f-(4f+5)-10=0
We get rid of parentheses
7f-4f-5-10=0
We add all the numbers together, and all the variables
3f-15=0
We move all terms containing f to the left, all other terms to the right
3f=15
f=15/3
f=5
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