9(z+1)+23=2(z-18)-2

Solution for 9(z+1)+23=2(z-18)-2 equation:

9(z+1)+23=2(z-18)-2

We move all terms to the left:

9(z+1)+23-(2(z-18)-2)=0

We multiply parentheses

9z-(2(z-18)-2)+9+23=0


We calculate terms in parentheses: -(2(z-18)-2), so:

2(z-18)-2

We multiply parentheses

2z-36-2

We add all the numbers together, and all the variables

2z-38

Back to the equation:

-(2z-38)


We add all the numbers together, and all the variables

9z-(2z-38)+32=0

We get rid of parentheses

9z-2z+38+32=0

We add all the numbers together, and all the variables

7z+70=0

We move all terms containing z to the left, all other terms to the right

7z=-70

z=-70/7

z=-10