5(h+3)-4=2(h-7)-2

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Solution for 5(h+3)-4=2(h-7)-2 equation: 



5(h+3)-4=2(h-7)-2

We move all terms to the left:

5(h+3)-4-(2(h-7)-2)=0

We multiply parentheses

5h-(2(h-7)-2)+15-4=0



We calculate terms in parentheses: -(2(h-7)-2), so:

2(h-7)-2

We multiply parentheses

2h-14-2

We add all the numbers together, and all the variables

2h-16

Back to the equation:

-(2h-16)



We add all the numbers together, and all the variables

5h-(2h-16)+11=0

We get rid of parentheses

5h-2h+16+11=0

We add all the numbers together, and all the variables

3h+27=0

We move all terms containing h to the left, all other terms to the right

3h=-27

h=-27/3

h=-9

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