7(b-4)=2(7b+4)

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Solution for 7(b-4)=2(7b+4) equation: 



7(b-4)=2(7b+4)

We move all terms to the left:

7(b-4)-(2(7b+4))=0

We multiply parentheses

7b-(2(7b+4))-28=0



We calculate terms in parentheses: -(2(7b+4)), so:

2(7b+4)

We multiply parentheses

14b+8

Back to the equation:

-(14b+8)



We get rid of parentheses

7b-14b-8-28=0

We add all the numbers together, and all the variables

-7b-36=0

We move all terms containing b to the left, all other terms to the right

-7b=36

b=36/-7

b=-5+1/7

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