4(b-4)=5(b+7)

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Solution for 4(b-4)=5(b+7) equation: 



4(b-4)=5(b+7)

We move all terms to the left:

4(b-4)-(5(b+7))=0

We multiply parentheses

4b-(5(b+7))-16=0



We calculate terms in parentheses: -(5(b+7)), so:

5(b+7)

We multiply parentheses

5b+35

Back to the equation:

-(5b+35)



We get rid of parentheses

4b-5b-35-16=0

We add all the numbers together, and all the variables

-1b-51=0

We move all terms containing b to the left, all other terms to the right

-b=51

b=51/-1

b=-51

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