(3x-5)-5x=3+2(x-1)

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Solution for (3x-5)-5x=3+2(x-1) equation: 



(3x-5)-5x=3+2(x-1)

We move all terms to the left:

(3x-5)-5x-(3+2(x-1))=0

We add all the numbers together, and all the variables

-5x+(3x-5)-(3+2(x-1))=0

We get rid of parentheses

-5x+3x-(3+2(x-1))-5=0



We calculate terms in parentheses: -(3+2(x-1)), so:

3+2(x-1)

determiningTheFunctionDomain
2(x-1)+3

We multiply parentheses

2x-2+3

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

-2x-(2x+1)-5=0

We get rid of parentheses

-2x-2x-1-5=0

We add all the numbers together, and all the variables

-4x-6=0

We move all terms containing x to the left, all other terms to the right

-4x=6

x=6/-4

x=-1+1/2

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