7(7p+4)(3p-1)=0

Solution for 7(7p+4)(3p-1)=0 equation:

7(7p+4)(3p-1)=0

We multiply parentheses ..

7(+21p^2-7p+12p-4)=0

We multiply parentheses

147p^2-49p+84p-28=0

We add all the numbers together, and all the variables

147p^2+35p-28=0

a = 147; b = 35; c = -28;
Δ = b2-4ac
Δ = 352-4·147·(-28)
Δ = 17689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17689}=133$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-133}{2*147}=\frac{-168}{294}
=-4/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+133}{2*147}=\frac{98}{294}
=1/3
$