8(-3+x)+4x=-2(1-6x)-2x

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Solution for 8(-3+x)+4x=-2(1-6x)-2x equation: 



8(-3+x)+4x=-2(1-6x)-2x

We move all terms to the left:

8(-3+x)+4x-(-2(1-6x)-2x)=0

We add all the numbers together, and all the variables

8(x-3)+4x-(-2(-6x+1)-2x)=0

We add all the numbers together, and all the variables

4x+8(x-3)-(-2(-6x+1)-2x)=0

We multiply parentheses

4x+8x-(-2(-6x+1)-2x)-24=0



We calculate terms in parentheses: -(-2(-6x+1)-2x), so:

-2(-6x+1)-2x

We add all the numbers together, and all the variables

-2x-2(-6x+1)

We multiply parentheses

-2x+12x-2

We add all the numbers together, and all the variables

10x-2

Back to the equation:

-(10x-2)



We add all the numbers together, and all the variables

12x-(10x-2)-24=0

We get rid of parentheses

12x-10x+2-24=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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