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6(x-2)+4=3(2x-4)
We move all terms to the left:
6(x-2)+4-(3(2x-4))=0
We multiply parentheses
6x-(3(2x-4))-12+4=0
We calculate terms in parentheses: -(3(2x-4)), so:We add all the numbers together, and all the variables
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
6x-(6x-12)-8=0
We get rid of parentheses
6x-6x+12-8=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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