7(5+2b)+b=65

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Solution for 7(5+2b)+b=65 equation: 



7(5+2b)+b=65

We move all terms to the left:

7(5+2b)+b-(65)=0

We add all the numbers together, and all the variables

7(2b+5)+b-65=0

We add all the numbers together, and all the variables

b+7(2b+5)-65=0

We multiply parentheses

b+14b+35-65=0

We add all the numbers together, and all the variables

15b-30=0

We move all terms containing b to the left, all other terms to the right

15b=30

b=30/15

b=2

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