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X2-22X-325=180
We move all terms to the left:
X2-22X-325-(180)=0
We add all the numbers together, and all the variables
X^2-22X-505=0
a = 1; b = -22; c = -505;
Δ = b2-4ac
Δ = -222-4·1·(-505)
Δ = 2504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2504}=\sqrt{4*626}=\sqrt{4}*\sqrt{626}=2\sqrt{626}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{626}}{2*1}=\frac{22-2\sqrt{626}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{626}}{2*1}=\frac{22+2\sqrt{626}}{2} $
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