7(3x-5)=4(x-4)-2

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Solution for 7(3x-5)=4(x-4)-2 equation: 



7(3x-5)=4(x-4)-2

We move all terms to the left:

7(3x-5)-(4(x-4)-2)=0

We multiply parentheses

21x-(4(x-4)-2)-35=0



We calculate terms in parentheses: -(4(x-4)-2), so:

4(x-4)-2

We multiply parentheses

4x-16-2

We add all the numbers together, and all the variables

4x-18

Back to the equation:

-(4x-18)



We get rid of parentheses

21x-4x+18-35=0

We add all the numbers together, and all the variables

17x-17=0

We move all terms containing x to the left, all other terms to the right

17x=17

x=17/17

x=1

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