6(1/3k-5=42

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Solution for 6(1/3k-5=42 equation: 



6(1/3k-5=42

We move all terms to the left:

6(1/3k-5-(42)=0



Domain of the equation: 3k-5-42!=0

We move all terms containing k to the left, all other terms to the right

3k!=47

k!=47/3

k!=15+2/3

k∈R



We multiply all the terms by the denominator


6(1=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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