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5(x+7)=6+(x-5)
We move all terms to the left:
5(x+7)-(6+(x-5))=0
We multiply parentheses
5x-(6+(x-5))+35=0
We calculate terms in parentheses: -(6+(x-5)), so:We get rid of parentheses
6+(x-5)
determiningTheFunctionDomain (x-5)+6
We get rid of parentheses
x-5+6
We add all the numbers together, and all the variables
x+1
Back to the equation:
-(x+1)
5x-x-1+35=0
We add all the numbers together, and all the variables
4x+34=0
We move all terms containing x to the left, all other terms to the right
4x=-34
x=-34/4
x=-8+1/2
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