7(2y-1)+3y=-3(y-2)+13

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Solution for 7(2y-1)+3y=-3(y-2)+13 equation: 



7(2y-1)+3y=-3(y-2)+13

We move all terms to the left:

7(2y-1)+3y-(-3(y-2)+13)=0

We add all the numbers together, and all the variables

3y+7(2y-1)-(-3(y-2)+13)=0

We multiply parentheses

3y+14y-(-3(y-2)+13)-7=0



We calculate terms in parentheses: -(-3(y-2)+13), so:

-3(y-2)+13

We multiply parentheses

-3y+6+13

We add all the numbers together, and all the variables

-3y+19

Back to the equation:

-(-3y+19)



We add all the numbers together, and all the variables

17y-(-3y+19)-7=0

We get rid of parentheses

17y+3y-19-7=0

We add all the numbers together, and all the variables

20y-26=0

We move all terms containing y to the left, all other terms to the right

20y=26

y=26/20

y=1+3/10

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