2(3n+1)=6(4n+3)+7

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Solution for 2(3n+1)=6(4n+3)+7 equation: 



2(3n+1)=6(4n+3)+7

We move all terms to the left:

2(3n+1)-(6(4n+3)+7)=0

We multiply parentheses

6n-(6(4n+3)+7)+2=0



We calculate terms in parentheses: -(6(4n+3)+7), so:

6(4n+3)+7

We multiply parentheses

24n+18+7

We add all the numbers together, and all the variables

24n+25

Back to the equation:

-(24n+25)



We get rid of parentheses

6n-24n-25+2=0

We add all the numbers together, and all the variables

-18n-23=0

We move all terms containing n to the left, all other terms to the right

-18n=23

n=23/-18

n=-1+5/18

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