(2x+14)+(68-x)=110

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Solution for (2x+14)+(68-x)=110 equation: 



(2x+14)+(68-x)=110

We move all terms to the left:

(2x+14)+(68-x)-(110)=0

We add all the numbers together, and all the variables

(2x+14)+(-1x+68)-110=0

We get rid of parentheses

2x-1x+14+68-110=0

We add all the numbers together, and all the variables

x-28=0

We move all terms containing x to the left, all other terms to the right

x=28

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