7(2y+1)-3=10(y+1)+8

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Solution for 7(2y+1)-3=10(y+1)+8 equation: 



7(2y+1)-3=10(y+1)+8

We move all terms to the left:

7(2y+1)-3-(10(y+1)+8)=0

We multiply parentheses

14y-(10(y+1)+8)+7-3=0



We calculate terms in parentheses: -(10(y+1)+8), so:

10(y+1)+8

We multiply parentheses

10y+10+8

We add all the numbers together, and all the variables

10y+18

Back to the equation:

-(10y+18)



We add all the numbers together, and all the variables

14y-(10y+18)+4=0

We get rid of parentheses

14y-10y-18+4=0

We add all the numbers together, and all the variables

4y-14=0

We move all terms containing y to the left, all other terms to the right

4y=14

y=14/4

y=3+1/2

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