3(2f+4)-2=3(2f-10)+5f

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Solution for 3(2f+4)-2=3(2f-10)+5f equation: 



3(2f+4)-2=3(2f-10)+5f

We move all terms to the left:

3(2f+4)-2-(3(2f-10)+5f)=0

We multiply parentheses

6f-(3(2f-10)+5f)+12-2=0



We calculate terms in parentheses: -(3(2f-10)+5f), so:

3(2f-10)+5f

We add all the numbers together, and all the variables

5f+3(2f-10)

We multiply parentheses

5f+6f-30

We add all the numbers together, and all the variables

11f-30

Back to the equation:

-(11f-30)



We add all the numbers together, and all the variables

6f-(11f-30)+10=0

We get rid of parentheses

6f-11f+30+10=0

We add all the numbers together, and all the variables

-5f+40=0

We move all terms containing f to the left, all other terms to the right

-5f=-40

f=-40/-5

f=+8

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