3(2f+4)-2=3(2f-10)+5

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Solution for 3(2f+4)-2=3(2f-10)+5 equation: 



3(2f+4)-2=3(2f-10)+5

We move all terms to the left:

3(2f+4)-2-(3(2f-10)+5)=0

We multiply parentheses

6f-(3(2f-10)+5)+12-2=0



We calculate terms in parentheses: -(3(2f-10)+5), so:

3(2f-10)+5

We multiply parentheses

6f-30+5

We add all the numbers together, and all the variables

6f-25

Back to the equation:

-(6f-25)



We add all the numbers together, and all the variables

6f-(6f-25)+10=0

We get rid of parentheses

6f-6f+25+10=0

We add all the numbers together, and all the variables

35!=0

There is no solution for this equation

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