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7(2x+3)-3(5x-2)=5(3x-4)-3(3x+4)
We move all terms to the left:
7(2x+3)-3(5x-2)-(5(3x-4)-3(3x+4))=0
We multiply parentheses
14x-15x-(5(3x-4)-3(3x+4))+21+6=0
We calculate terms in parentheses: -(5(3x-4)-3(3x+4)), so:We add all the numbers together, and all the variables
5(3x-4)-3(3x+4)
We multiply parentheses
15x-9x-20-12
We add all the numbers together, and all the variables
6x-32
Back to the equation:
-(6x-32)
-1x-(6x-32)+27=0
We get rid of parentheses
-1x-6x+32+27=0
We add all the numbers together, and all the variables
-7x+59=0
We move all terms containing x to the left, all other terms to the right
-7x=-59
x=-59/-7
x=8+3/7
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