2/3x=10x=

Solution for 2/3x=10x= equation:

2/3x=10x=

We move all terms to the left:

2/3x-(10x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

-10x+2/3x=0

We multiply all the terms by the denominator


-10x*3x+2=0

Wy multiply elements

-30x^2+2=0

a = -30; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-30)·2
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*-30}=\frac{0-4\sqrt{15}}{-60}
=-\frac{4\sqrt{15}}{-60}
=-\frac{\sqrt{15}}{-15}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*-30}=\frac{0+4\sqrt{15}}{-60}
=\frac{4\sqrt{15}}{-60}
=\frac{\sqrt{15}}{-15}
$