i(72*i+835)-60=100

Solution for i(72*i+835)-60=100 equation:

i(72i+835)-60=100

We move all terms to the left:

i(72i+835)-60-(100)=0

We add all the numbers together, and all the variables

i(72i+835)-160=0

We multiply parentheses

72i^2+835i-160=0

a = 72; b = 835; c = -160;
Δ = b2-4ac
Δ = 8352-4·72·(-160)
Δ = 743305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(835)-\sqrt{743305}}{2*72}=\frac{-835-\sqrt{743305}}{144}
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(835)+\sqrt{743305}}{2*72}=\frac{-835+\sqrt{743305}}{144}
$