7(2n+4)=2+5(3n-3)

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Solution for 7(2n+4)=2+5(3n-3) equation: 



7(2n+4)=2+5(3n-3)

We move all terms to the left:

7(2n+4)-(2+5(3n-3))=0

We multiply parentheses

14n-(2+5(3n-3))+28=0



We calculate terms in parentheses: -(2+5(3n-3)), so:

2+5(3n-3)

determiningTheFunctionDomain
5(3n-3)+2

We multiply parentheses

15n-15+2

We add all the numbers together, and all the variables

15n-13

Back to the equation:

-(15n-13)



We get rid of parentheses

14n-15n+13+28=0

We add all the numbers together, and all the variables

-1n+41=0

We move all terms containing n to the left, all other terms to the right

-n=-41

n=-41/-1

n=+41

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