7(2n+4)=-2+5(3n-3)

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Solution for 7(2n+4)=-2+5(3n-3) equation: 



7(2n+4)=-2+5(3n-3)

We move all terms to the left:

7(2n+4)-(-2+5(3n-3))=0

We multiply parentheses

14n-(-2+5(3n-3))+28=0



We calculate terms in parentheses: -(-2+5(3n-3)), so:

-2+5(3n-3)

determiningTheFunctionDomain
5(3n-3)-2

We multiply parentheses

15n-15-2

We add all the numbers together, and all the variables

15n-17

Back to the equation:

-(15n-17)



We get rid of parentheses

14n-15n+17+28=0

We add all the numbers together, and all the variables

-1n+45=0

We move all terms containing n to the left, all other terms to the right

-n=-45

n=-45/-1

n=+45

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