7(2n+1)=7(4n+9)+5

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Solution for 7(2n+1)=7(4n+9)+5 equation: 



7(2n+1)=7(4n+9)+5

We move all terms to the left:

7(2n+1)-(7(4n+9)+5)=0

We multiply parentheses

14n-(7(4n+9)+5)+7=0



We calculate terms in parentheses: -(7(4n+9)+5), so:

7(4n+9)+5

We multiply parentheses

28n+63+5

We add all the numbers together, and all the variables

28n+68

Back to the equation:

-(28n+68)



We get rid of parentheses

14n-28n-68+7=0

We add all the numbers together, and all the variables

-14n-61=0

We move all terms containing n to the left, all other terms to the right

-14n=61

n=61/-14

n=-4+5/14

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