(n+n+0.6)2=(n+0.1+2n)2

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Solution for (n+n+0.6)2=(n+0.1+2n)2 equation: 



(n+n+0.6)2=(n+0.1+2n)2

We move all terms to the left:

(n+n+0.6)2-((n+0.1+2n)2)=0

We add all the numbers together, and all the variables

(2n+0.6)2-((3n+0.1)2)=0

We multiply parentheses

4n-((3n+0.1)2)+1.2=0



We calculate terms in parentheses: -((3n+0.1)2), so:

(3n+0.1)2

We multiply parentheses

6n+0.2

Back to the equation:

-(6n+0.2)



We get rid of parentheses

4n-6n-0.2+1.2=0

We add all the numbers together, and all the variables

-2n+1=0

We move all terms containing n to the left, all other terms to the right

-2n=-1

n=-1/-2

n=1/2

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