6x2+12x-4x-8=0

Solution for 6x2+12x-4x-8=0 equation:

6x^2+12x-4x-8=0

We add all the numbers together, and all the variables

6x^2+8x-8=0

a = 6; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·6·(-8)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-16}{2*6}=\frac{-24}{12}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+16}{2*6}=\frac{8}{12}
=2/3
$