2/5(x+1)=4+1/2(2x-9)

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Solution for 2/5(x+1)=4+1/2(2x-9) equation: 



2/5(x+1)=4+1/2(2x-9)

We move all terms to the left:

2/5(x+1)-(4+1/2(2x-9))=0



Domain of the equation: 5(x+1)!=0

x∈R





Domain of the equation: 2(2x-9))!=0

x∈R



We calculate fractions


(4x2/(5(x+1)*2(2x-9)))+(-5xx/(5(x+1)*2(2x-9)))=0



We calculate terms in parentheses: +(4x2/(5(x+1)*2(2x-9))), so:

4x2/(5(x+1)*2(2x-9))

We multiply all the terms by the denominator


4x2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)





We calculate terms in parentheses: +(-5xx/(5(x+1)*2(2x-9))), so:

-5xx/(5(x+1)*2(2x-9))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

4x^2-5xx=0

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