3x(4-x)=15

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Solution for 3x(4-x)=15 equation: 



3x(4-x)=15

We move all terms to the left:

3x(4-x)-(15)=0

We add all the numbers together, and all the variables

3x(-1x+4)-15=0

We multiply parentheses

-3x^2+12x-15=0

a = -3; b = 12; c = -15;
Δ = b2-4ac
Δ = 122-4·(-3)·(-15)
Δ = -36
Delta is less than zero, so there is no solution for the equation

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