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6x-3/3x=36
We move all terms to the left:
6x-3/3x-(36)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
6x*3x-36*3x-3=0
Wy multiply elements
18x^2-108x-3=0
a = 18; b = -108; c = -3;
Δ = b2-4ac
Δ = -1082-4·18·(-3)
Δ = 11880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11880}=\sqrt{36*330}=\sqrt{36}*\sqrt{330}=6\sqrt{330}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-6\sqrt{330}}{2*18}=\frac{108-6\sqrt{330}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+6\sqrt{330}}{2*18}=\frac{108+6\sqrt{330}}{36} $
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