1(y-8)=-4(y+8)

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Solution for 1(y-8)=-4(y+8) equation:



1(y-8)=-4(y+8)
We move all terms to the left:
1(y-8)-(-4(y+8))=0
We calculate terms in parentheses: -(-4(y+8)), so:
-4(y+8)
We multiply parentheses
-4y-32
Back to the equation:
-(-4y-32)
We get rid of parentheses
1(y-8)+4y+32=0
We add all the numbers together, and all the variables
4y+1(y-8)+32=0
We move all terms containing y to the left, all other terms to the right
4y+1(y-8)=-32

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