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6x-4/9x=1
We move all terms to the left:
6x-4/9x-(1)=0
Domain of the equation: 9x!=0We multiply all the terms by the denominator
x!=0/9
x!=0
x∈R
6x*9x-1*9x-4=0
Wy multiply elements
54x^2-9x-4=0
a = 54; b = -9; c = -4;
Δ = b2-4ac
Δ = -92-4·54·(-4)
Δ = 945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{945}=\sqrt{9*105}=\sqrt{9}*\sqrt{105}=3\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{105}}{2*54}=\frac{9-3\sqrt{105}}{108} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{105}}{2*54}=\frac{9+3\sqrt{105}}{108} $
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