6x-4(2x-8)=5(x-2)

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Solution for 6x-4(2x-8)=5(x-2) equation: 



6x-4(2x-8)=5(x-2)

We move all terms to the left:

6x-4(2x-8)-(5(x-2))=0

We multiply parentheses

6x-8x-(5(x-2))+32=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

-2x-(5x-10)+32=0

We get rid of parentheses

-2x-5x+10+32=0

We add all the numbers together, and all the variables

-7x+42=0

We move all terms containing x to the left, all other terms to the right

-7x=-42

x=-42/-7

x=+6

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