x(7x-7)=(7x+1)(x-1)

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Solution for x(7x-7)=(7x+1)(x-1) equation:



x(7x-7)=(7x+1)(x-1)
We move all terms to the left:
x(7x-7)-((7x+1)(x-1))=0
We multiply parentheses
7x^2-7x-((7x+1)(x-1))=0
We multiply parentheses ..
7x^2-((+7x^2-7x+x-1))-7x=0
We calculate terms in parentheses: -((+7x^2-7x+x-1)), so:
(+7x^2-7x+x-1)
We get rid of parentheses
7x^2-7x+x-1
We add all the numbers together, and all the variables
7x^2-6x-1
Back to the equation:
-(7x^2-6x-1)
We add all the numbers together, and all the variables
7x^2-7x-(7x^2-6x-1)=0
We get rid of parentheses
7x^2-7x^2-7x+6x+1=0
We add all the numbers together, and all the variables
-1x+1=0
We move all terms containing x to the left, all other terms to the right
-x=-1
x=-1/-1
x=1

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