6x-33=3(1+8x)

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Solution for 6x-33=3(1+8x) equation: 



6x-33=3(1+8x)

We move all terms to the left:

6x-33-(3(1+8x))=0

We add all the numbers together, and all the variables

6x-(3(8x+1))-33=0



We calculate terms in parentheses: -(3(8x+1)), so:

3(8x+1)

We multiply parentheses

24x+3

Back to the equation:

-(24x+3)



We get rid of parentheses

6x-24x-3-33=0

We add all the numbers together, and all the variables

-18x-36=0

We move all terms containing x to the left, all other terms to the right

-18x=36

x=36/-18

x=-2

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