(2/3)x+x=22

Solution for (2/3)x+x=22 equation:

(2/3)x+x=22

We move all terms to the left:

(2/3)x+x-(22)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x+x-22=0

We add all the numbers together, and all the variables

x+(+2/3)x-22=0

We multiply parentheses

2x^2+x-22=0

a = 2; b = 1; c = -22;
Δ = b2-4ac
Δ = 12-4·2·(-22)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{177}}{2*2}=\frac{-1-\sqrt{177}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{177}}{2*2}=\frac{-1+\sqrt{177}}{4}
$