6x-1=4(x-3)+5

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Solution for 6x-1=4(x-3)+5 equation:



6x-1=4(x-3)+5
We move all terms to the left:
6x-1-(4(x-3)+5)=0
We calculate terms in parentheses: -(4(x-3)+5), so:
4(x-3)+5
We multiply parentheses
4x-12+5
We add all the numbers together, and all the variables
4x-7
Back to the equation:
-(4x-7)
We get rid of parentheses
6x-4x+7-1=0
We add all the numbers together, and all the variables
2x+6=0
We move all terms containing x to the left, all other terms to the right
2x=-6
x=-6/2
x=-3

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